Path: utzoo!attcan!uunet!virtech!cpcahil From: cpcahil@virtech.UUCP (Conor P. Cahill) Newsgroups: comp.unix.questions Subject: Re: Problem with make Keywords: make for sysV Message-ID: <1212@virtech.UUCP> Date: 30 Sep 89 11:53:08 GMT References: <715@bbking.KSP.Unisys.COM> <11169@smoke.BRL.MIL> <1989Sep29.164831.26616@wash08.uucp> Organization: Virtual Technologies Inc Lines: 43 In article <1989Sep29.164831.26616@wash08.uucp>, rae98@wash08.uucp (Robert A. Earl) writes: > Can you read in a variable for use in the makefile? > i.e.: > read a;echo $(a) sort of. You can read in a shell variable, but not a makefile variable. The mechanism is something like the following: target: echo "enter system name: \c"; \ read sysname; \ echo "sysname is $$sysname" Note that each line ends with a line continuation '\' so that make passes all three lines to the same shell. > Alternatively, can you pass args through make to be used in the makefile? > What I really want to do is: > > make tar (system_name) > and have the makefile generate a tar file and send it to system_name. How about: make tar sys=uunet and in the makefile: tar: /* stuff to generate file */ if [ -z "$(sys)" ]; then \ echo "No sys specified, file not transferred.";\ else \ echo "transferring file to $(sys)"; \ uucp tarfile $(sys)!tarfile; \ fi -- +-----------------------------------------------------------------------+ | Conor P. Cahill uunet!virtech!cpcahil 703-430-9247 ! | Virtual Technologies Inc., P. O. Box 876, Sterling, VA 22170 | +-----------------------------------------------------------------------+