Xref: utzoo rec.puzzles:2269 sci.electronics:4355
Path: utzoo!utgpu!watmath!watcgl!awpaeth
From: awpaeth@watcgl.waterloo.edu (Alan Wm Paeth)
Newsgroups: rec.puzzles,sci.electronics
Subject: Re: Resistor Puzzle
Message-ID: <7079@watcgl.waterloo.edu>
Date: 1 Dec 88 18:32:07 GMT
References: <6951@watcgl.waterloo.edu>
Reply-To: awpaeth@watcgl.waterloo.edu (Alan Wm Paeth)
Distribution: rec
Organization: U. of Waterloo, Ontario
Lines: 23

In <6951@watcgl.waterloo.edu> awpaeth@watcgl.waterloo.edu (Alan Paeth) writes:
>-----------------------------------------------------------------------------
>PUZZLE: using four resistors construct a "decade" good for (at least) the
>range 1 to 16 ohms, inclusive. No restrictions on wiring or resistor values.
[make that a "double" decade, good from 0-19 ohms]
>-----------------------------------------------------------------------------

I know only one solution. One can nearly make the 1-10 ohm decade with just
three resistors, wired in the following fashion (+ is series, | is parallel):

resistors: 2, 3, 6.
wiring: 1. 2|3|6 2. 2 3. 3 4. 2+(3|6) 5. 2+3 6. 6 7. ? 8. 2+6 9. 3+6 11. 2+3+6

this leaves holes at 7 and 10 ohms. Adding a 7 ohm resistor to extend the range
causes the problem to crop up again at 14 ohms; adding a 10 ohm resistor widens
the range by 10+[1..6,8..9,11] or to 19 ohms continuous, sans seven. The gap at
seven ohms can be finessed as ((10+2)|6)+3 -- this is the most intricate net.

In general, the identities 2a|2a = a, 3|6 = 2, 6|12 = 4, 4|12 = 3 are helpful.

    /Alan Paeth
    Computer Graphics Laboratory
    University of Waterloo