Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site brl-tgr.ARPA Path: utzoo!linus!philabs!cmcl2!harvard!seismo!brl-tgr!tgr!stephany.WBST@Xerox.ARPA From: stephany.WBST@Xerox.ARPA Newsgroups: net.ham-radio Subject: Re: modulation question Message-ID: <2861@brl-tgr.ARPA> Date: Tue, 5-Nov-85 13:37:11 EST Article-I.D.: brl-tgr.2861 Posted: Tue Nov 5 13:37:11 1985 Date-Received: Fri, 8-Nov-85 07:17:26 EST Sender: news@brl-tgr.ARPA Lines: 11 re: problem with power in a balanced modulator I think your problem is that you assumed that the diode characteristics fit a pure square law . Actual, ideal diodes contain higher terms, third, fourth, etc. power. An ideal diode is I=Io(1-exp(eE/kT)), which must be expanded in a power series. In the balanced configuration all odd terms cancel so you are left with the square, fourth power and higher even powers. Your math only took into account the first square term. I did not work it out but I believe that is the problem. Joe N2XS