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From: karn@petrus.UUCP (Phil R. Karn)
Newsgroups: net.analog,net.puzzle
Subject: Re: Thevinin/Norton equivalents (SPOILER)
Message-ID: <623@petrus.UUCP>
Date: Fri, 4-Oct-85 17:24:04 EDT
Article-I.D.: petrus.623
Posted: Fri Oct  4 17:24:04 1985
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Xref: watmath net.analog:480 net.puzzle:1028

You can't, if you're allowed only to see how the two terminals behave to
external circuits; they're equivalent.

However, with the terminals open-circuited, the black box with the current
source will be dissipating 1 watt of power, while the the one with the
voltage source will not be dissipating anything. Short the terminals and the
situation reverses. Stick each box into a picnic cooler with a thermometer,
and wait. This is the only way I see to solve the puzzle.

Phil