Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.2 9/18/84; site warwick.UUCP Path: utzoo!linus!philabs!cmcl2!seismo!mcvax!ukc!warwick!msp From: msp@warwick.UUCP (Mike Paterson) Newsgroups: net.math Subject: Re: probability formula needed Message-ID: <140@ubu.warwick.UUCP> Date: Fri, 20-Sep-85 11:56:43 EDT Article-I.D.: ubu.140 Posted: Fri Sep 20 11:56:43 1985 Date-Received: Wed, 25-Sep-85 07:43:56 EDT References: <3210001@csd2.UUCP> <6621@boring.UUCP> Organization: Computer Science, Warwick University, UK Lines: 12 Xpath: warwick ubu The probability needed can be viewed as the probability of getting two adjacent picture cards with different values (e.g. JK) in a random deal. The probability of failure seems to be the coefficient of x^38 in 41!40!/52!.e^x.(24+24x+12x^2+x^3)^3 My pocket calculator is smoking but the answer looks like 49220186227/447219915450 (about .110058129) This would give a winning percentage of a tiny bit below 89.0% compared with Lambert Meertens' 88.7%. Any other offers? Mike Paterson