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From: maxg@tekig4.UUCP (Max Guernsey)
Newsgroups: net.micro
Subject: Re: Z-100 blows away IBM-AT
Message-ID: <119@tekig4.UUCP>
Date: Thu, 6-Jun-85 00:23:22 EDT
Article-I.D.: tekig4.119
Posted: Thu Jun  6 00:23:22 1985
Date-Received: Mon, 12-Aug-85 06:11:14 EDT
References: <463@bgsuvax.UUCP> <327@moncol.UUCP>
Reply-To: maxg@tekig4ernsey.UUCP (Max Guernsey)
Organization: Tektronix, Beaverton OR
Lines: 32
Summary: 

In article <327@moncol.UUCP> john@moncol.UUCP (John Ruschmeyer) writes:
>>>Using a standard BASIC benchmark, the Z-100 (8/16-bit 8088) blows
>>>away an IBM-AT (16-bit 80286 at 6 MHz).
>>>
>>>the progam:
>>>
>>>5 TIME$="00:00:00"
>>>10 FOR X=1 TO 10000
>>>20 IF SQR(X)<>INT(SQR(X)) THEN 40
>>>30 PRINT SQR(X),
>>>40 NEXT X
>>>45 PRINT TIME$
>>>50 END
...
>>>The time for the 6 MHz IBM-AT is 1 min, 13 sec
...
>COMPUTER       VERSION               OUTPUT DIRECTED TO            TIME
>========       =======               ==================            ====
...
>AT&T 6300      640k			  screen		   0:32
>(8mhz 8086)


Now for my $.02 worth.  I have an AT at work and a 6300 at home and I tried out the benchmark just to see.  It's true.

The AT when booted with and unformatted C: and nothing in A: still "comes up"
in "cassett basic" I believe.  So the AT is probably still looking to ROM to
find some of the routines.

Would this explain the AT's turtle like behavior?

Max Guernsey, jr.