Message-ID: <331@houxz.UUCP>
Date: Mon, 18-Jul-83 15:36:47 EDT
Article-I.D.: houxz.331
Posted: Mon Jul 18 15:36:47 1983
Date-Received: Tue, 19-Jul-83 13:30:49 EDT
References: <187@wdl1.UUCP>
Organization: Bell Labs, Holmdel NJ
Lines: 12

Spy would never make it as one.  He is wrong on all counts.
The star is not solid but full of emptyness, so to speak.
Consequently, the fact that the surface is small relative to
the volume is important.  This is true for all levels of the
Death Star, if you think of it as successive shells.

Also, there is no significant gravitation from the mass of the
star.  Its size is no bigger than a small planet, and its density
is many orders of magnitude less.  Consequently, gravity is unmeasureable.
In addition, as you get closer to the center of mass, the gravitational
attraction decreases, reaching zero at the center.  Thus the spherical
shape has no measurable effect on the gravitational fields.